Click the Next button to see that West leads the ♦5 (4th from good, second from xxx/xxxx) and we win in hand.
We can count eight tricks, with two spades, one heart, two diamonds and three clubs, but this may involve losing the lead twice. Entries are also a concern, as we are in hand now but with only one guaranteed entry left.
What are our options?
If spades are 3-3, then we could play three rounds of the suit. This would generate an additional two winners but would lose the lead in the process. If would also bring our total to 8 tricks and we still need to establish a second club trick. Establishing the club trick would have to be done first because of the entry situation.
A second option is just to play on clubs and try for a fourth trick. This would need West to hold ♣K or ♣Kx, or ♣Kxx and East to hold the ♥K as we'll need an additional entry.
A third option is to play on hearts. This suit combination is one where the best line for four tricks is not an intuitive one - an exercise for the reader is to work out what the best line is! However, is the best line right here? Using tools, such as SuitPlay, give answers that presume unlimited entries, which is not the case here.
And we need to consider the dangers. If diamonds are 4-4, then we will lose two diamonds but have good chances if we play the right suit. If diamonds are 6-2, especially possible when the opposition do not play a weak 2♦, then we need a line that takes out West's entry first. And if diamonds are 5-3, then we probably do not have a chance unless West holds the ♣K or we can establish sufficient tricks without a second club trick.
What do you fancy?
More thoughts on this next year.
Update: this thread on the BBO Forums shows the thoughts of the forum regulars and illustrates the main lines.